this post was submitted on 21 Dec 2024
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I'm sorry, but even without knowing about the mod operator, this is inefficient and over engineered. Why have a loop at all?
no loop required...
having said that, I can totally see how that was missed in a high pressure interview. I hate interviews like that!
edit: Ha ha... isEven...not isPositive... I'm tired. ignore me!
That would be isPositive.
Without using the modulo operator you'd essentially have to reimplement it. Divide the number by 2 and round down. Multiply that by 2 and then subtract it from the original number.
isEven(10) results in 10-10==0 (true) whereas isEven(13) results in 13-12==0 (false).
Minor simplification: this works even without taking absolute value first of you use fix instead of floor.
Edit: I don't know if fix is in the stock math library on second thought...