this post was submitted on 12 Mar 2024
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Mostly, yeah. But sometimes you really just need to know the order of magnitude, which is a process kinda similar to rounding, but does lose a digit in the process, so you could kinda argue—if you squint a little—that it's "rounding to zero digits".
That's basically my reasoning, yeah. Specifically, in floating point notation; if you get rid of all the mantissa bits, you'd be left with 1 * 2^0. I suppose it could be 0 * 2^0, but a leading 1 is implied, since virtually all numbers are nonzero.
Small correction: Pi lies between 2^1 and 2^2, so its floating-point exponent is 1. With all the mantissa bits cleared you'd be left with 1 * 2^1, not 1 * 2^0.