this post was submitted on 06 Nov 2023
140 points (89.8% liked)

Science Memes

11205 readers
1586 users here now

Welcome to c/science_memes @ Mander.xyz!

A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.



Rules

  1. Don't throw mud. Behave like an intellectual and remember the human.
  2. Keep it rooted (on topic).
  3. No spam.
  4. Infographics welcome, get schooled.

This is a science community. We use the Dawkins definition of meme.



Research Committee

Other Mander Communities

Science and Research

Biology and Life Sciences

Physical Sciences

Humanities and Social Sciences

Practical and Applied Sciences

Memes

Miscellaneous

founded 2 years ago
MODERATORS
 

OC just for you! ♥️

you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 7 points 1 year ago* (last edited 1 year ago) (1 children)

From a purely utilitarianism perspective, assuming all utility is linear and unscaled:

5/6 chance I'm on the side track * 1 person saved = 5/6

1/6 chance on the main track * 1/10 chance my switch is real * 10 people saved = 1/6

Seems pretty clear that you should not flip the switch. However, if I am on the main track, this thinking will lead to no-one flipping the switch and no lives saved whereas everyone thinking it will lead to a guaranteed save -> utility of 10/6.

If I can assume more than half the people can be rational and will think like me then I should flip the switch.

If I cannot, I should not flip the switch.

[–] aurele 12 points 1 year ago* (last edited 1 year ago) (1 children)

Except that if people are chosen randomly there is 2/3 chance that you are on the main track according to Bayes. Let's assume there are 10 people.

The probability to be chosen is 1/6 (all are chosen if 6 is rolled) + (5/6) × (1/10) (only one is chosen to go to the side track if 1-5 is rolled) = 15/60 = 1/4.

The probability that you are on the side track knowing that you have been chosen is the probability that you have been chosen knowing that the side track is selected (1/10) × the probability that the side track is selected (5/6) divided by the probability for you to be selected at all (1/4), so (1/10)×(5/6)/(1/4) = 20/60 = 1/3. So there is a 2/3 chance that you are on the main track.

If you do not flip the switch, (2/3)×10 = 20/3 people die.

If you flip the switch, 1/3 (you if on side track) + 10 × 2/3 × 9 / 10 (switch misfires 9 out of 10 times if on the main track) = 190/30 = 19/3 die. This is slightly better than not flipping the switch, you save 1/3 people more. That's an arm and a leg.

[–] [email protected] 5 points 1 year ago (1 children)

I wouldn't assume anything about the number of people and how anyone was chosen. All I know is I'm on the track.

[–] [email protected] 4 points 1 year ago

But if you say you are on each track with p=1/2 then you also assume (different) details about how you were chosen

The task is unclear here, you have to make an assumption. I don't know which is intended.