this post was submitted on 22 Jun 2023
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submitted 1 year ago* (last edited 1 year ago) by [email protected] to c/[email protected]
 

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[–] [email protected] 3 points 1 year ago* (last edited 1 year ago) (3 children)

Both! Critically, the contents of box B depend on the machine's prediction, not on whether it was correct or not (i.e. not on your subsequent choice). So it's effectively a 50/50 coin toss and irrelevant to the decision-making process. Let's break down the possibilities:

Machine predicts I take B only, box B contains $1B:

  • I take B only - I get $1B.
  • I take both - I get $1.001B

Machine predicts I take both, box B is empty:

  • I take B only - I get nothing.
  • I take both - I get $1M.

Regardless of what the machine predicts, taking both boxes produces a better result than taking only B. The question can be restated as "Do you take $1M plus a chance to win $1B or would you prefer $0 plus the same chance to win $1B?", in which case the answer becomes intuitively obvious.

[–] [email protected] 1 points 1 year ago (2 children)

But if it's true that the machine can perfectly predict what you will choose, then by definition your choice will be the same its prediction. In which case, you should choose one box.

[–] annegreen 2 points 1 year ago

Though OP never actually stated that the machine can perfectly predict the future. If that’s the case, then yes, you should just take box B. But we’re not given any information about how it makes its prediction. If @[email protected] is correct in assuming it’s a 50-50, then their strategy of taking both is best. It really depends on how the machine makes its prediction.

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