this post was submitted on 16 Jun 2023
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[–] [email protected] 6 points 1 year ago (2 children)

Ok some of these I understand but what the fuck. Why.

[–] [email protected] 3 points 1 year ago* (last edited 1 year ago) (2 children)

I'm not sure if you really want to know, but:

greater than, smaller than, will cast the type so it will be 0>0 which is false, ofcourse. 0>=0 is true.

Now == will first compare types, they are different types so it's false.

Also I'm a JavaScript Dev and if I ever see someone I work with use these kind of hacks I'm never working together with them again unless they apologize a lot and wash their dirty typing hands with.. acid? :-)

edit: as several people already pointed out, my answer is not accurate. The real solution was mentioned by mycus

[–] [email protected] 4 points 1 year ago

isn't === the one that compare types first?

I just tried on node and 0 == '0' returns true


found the real reason

[–] [email protected] 1 points 1 year ago (1 children)

Not a JavaScript dev here, but I work with it. Doesn't "==" do type coercion, though? Isn't that why "===" exists?

As far as I know the operators ">=" and "<=" are implemented as the negation of "<" and ">" respectively. Why: because when you are working with sticky ordered sets, like natural numbers, those operators work.

Thus "0<=0" -> "!(0>0)" -> "!(false)" -> "true"

Correct me if my thinking is wrong though.

[–] [email protected] 1 points 1 year ago

So will null <= 0 returns true?

Why tho

[–] [email protected] 1 points 1 year ago

a >= b, is equivalent to, !(a < b)