this post was submitted on 14 May 2024
186 points (98.4% liked)

PC Gaming

8635 readers
529 users here now

For PC gaming news and discussion. PCGamingWiki

Rules:

  1. Be Respectful.
  2. No Spam or Porn.
  3. No Advertising.
  4. No Memes.
  5. No Tech Support.
  6. No questions about buying/building computers.
  7. No game suggestions, friend requests, surveys, or begging.
  8. No Let's Plays, streams, highlight reels/montages, random videos or shorts.
  9. No off-topic posts/comments, within reason.
  10. Use the original source, no clickbait titles, no duplicates. (Submissions should be from the original source if possible, unless from paywalled or non-english sources. If the title is clickbait or lacks context you may lightly edit the title.)

founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
[โ€“] [email protected] 4 points 6 months ago (1 children)

From the technical sense it doesn't have to have 4 drives

Please explain how you think you can distribute two sets of parity data across a three drive array?

[โ€“] [email protected] 0 points 6 months ago* (last edited 6 months ago)

Drive 1: A, Drive 2: 1/2 A, Drive 3: 2/2 A. Drive 2 + Drive 3 = Drive 1. Hmm that would only be one set of the party though. So you could also add 1/2 of A to Drive 1, and 2/2 to Drive 2 so that the parity on Drive 1 + Drive 2 = Drive 3. Which is extremely silly, and doesn't make a lot of sense to use in the real world.