this post was submitted on 25 Nov 2023
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I need to reach a certain amount of space but have a limited budget. I saw these refurb drives on bargainhardware a while back and waited through BF to see if anything close to the £/TB came up. Unfortunately the UK doesn't seem to have seen any such deals.

My budget is limited, I also already have some older smaller drives that would form part of the array. I would likely be using unRAID with 2 of the purchased drives being Parity drives, or the same with SnapRAID. I feel that 2x Parity is neccessary to ensure that I can protect against inevitable failure, my current 4TB drives approach 5 years in use, and the refurb drives are between 3 and 5 years old according to the seller (datacentre use). If you feel you can suggest better alternatives or new drives that fit the bill please let me know. I feel that I would be unlikely to return a storage drive under warranty.

  • 4x 10TB HGST HUH721010ALN600 £86.40 - £345.60. 20TB pool, approx 5 years usage.
  • 3x 12TB WD HC520 HUH721212ALE601 £132 - £396. 12TB pool (higher parity ceiling), approx 3 years usage.
  • 3x 12TB EMC Seagate ST12000NM005G £120 - £360. 12TB pool (higher parity ceiling), unknown time in use, Seagate?

I don't want to go above £400, I have a need for at least 10TB in the pool and in my mind 2 Parity drives is mitigating some of the risk with refurb drives. Am I going about this the wrong way?

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[–] [email protected] 1 points 11 months ago (1 children)

You need at least like 5-6 drives for double parity to be economical. Aside from that you need backup.

[–] [email protected] 1 points 11 months ago (1 children)

Thank you - I have 4 other 4TB drives that would make up the pool and several 2TB drives. I would estimate this to be a pool size starting at 5+ drives and rising, so I wanted to get the parity in place now. But this makes sense, I am considering how to approach a 1 parity situaiton.

[–] [email protected] 1 points 11 months ago

Note that any sane RAID software will limit the size used on each drive to the size of the smallest drive in the array.