this post was submitted on 15 Aug 2023
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Programming Challenges
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Welcome to the programming.dev challenge community!
Three challenges will be posted every week to complete
- Tuesday (Easy)
- Thursday (Medium)
- Saturday (Hard)
Easy challenges will give 1 point, medium will give 2, and hard will give 3. If you have the fastest time or use the least amount of characters you will get a bonus point (in ties everyone gets the bonus point)
Exact duplicate solutions are not allowed and will not give you any points. Submissions on a challenge will be open for a week.
A leaderboard will be posted every month showing the top people for that month
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Hi! I created a stack-based language called kcats that is meant to be a simple and powerful language and good for small programs like this one. You can read more about it here: https://skyrod-vactai.github.io/kcats/book-of-kcats.html
Here's the solution in kcats (assumes the input is on the stack):
A bit of explanation: First place a mapping of opening bracket to its matching closing bracket on the stack. Then place the empty result which will be modified as we go. Float the input to the top of stack. Then an if statement. The first part of the if statement is the condition: look up the matching close bracket to the last item in the result, see if it equals the current character. If the condition is true, drop the current character and the last item in the result. If not, put the item into the result. Then 'step' runs that if statement on each character of the input. Finally, when we're done we don't need the mapping of matching brackets anymore, and we drop it.