this post was submitted on 14 Aug 2024
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No Stupid Questions

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[–] [email protected] 18 points 3 months ago* (last edited 3 months ago) (1 children)

Edit: I was off by a big order of magnitude, see my reply to this comments reply.

~~No.~~ You are also forgetting the density of the sun increases with depth. For instance, if it's heading for the core - the solar core is about 155g/cm^3. Where as earth is 5.5g/cm3.

~~Essentially, going 0.9C is going to impact the sun, and we can say the incoming earth object is going to classically hit with 4.9*10^24 J.~~

~~At this size and and energy, we compare it to the rest energy of the entire sun (this isn't how we would actually do it) but the sun has a total resting mass energy equivalence of like 1.8x10^41 J.~~

~~The energy of the earth like object impacting the sun is 0.000000000000000027%.~~

~~The sun effectively doesn't even know it happened.~~

[–] [email protected] 10 points 3 months ago (1 children)

I knew my crap science would get the real scientists in the comments, good point about the density. It would just sort of harmlessly splat.

[–] [email protected] 5 points 3 months ago

Now hold on, I did my math wrong. It was far too late at night. I used C=300000 not 3*10^8.

That gives us an impact energy, classically, of 5.37*10^41 J.

So that is about 3 times the kinetic energy than the engery at rest of Sol.

Sol is not at rest, further, we have non- insignificant factors at play here.

Sol is orbiting Sagittarius A* at 250km/s. Additionally, we have the general relativistic relationship between Sol and our massive projectile.

I'm going to work on modeling this, it got far more interesting.