Science Memes

11261 readers

2753 users here now

Welcome to c/science_memes @ Mander.xyz!

A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.

Rules

Don't throw mud. Behave like an intellectual and remember the human.
Keep it rooted (on topic).
No spam.
Infographics welcome, get schooled.

This is a science community. We use the Dawkins definition of meme.

Research Committee

[email protected]

Other Mander Communities

Science and Research

Biology and Life Sciences

Physical Sciences

Humanities and Social Sciences

Practical and Applied Sciences

Memes

Miscellaneous

founded 2 years ago

MODERATORS

[email protected]

416

Let π = 5 (files.catbox.moe)

submitted 7 months ago by [email protected] to c/[email protected]

36 comments fedilink hide all child comments

cross-posted from: https://lemm.ee/post/29980757

Let π = 5

you are viewing a single comment's thread
view the rest of the comments

[–] [email protected] 2 points 7 months ago* (last edited 7 months ago) (1 children)

Better question: What curvature of space is necessary for the apparent value of π to be 5?

~~honestly I don't know if there is any way to measure curvature of space , but its slightly more curved than the surface of a ball (where π=~4.712)~~

edit : its more complex than that and topology of non euclidean spaces hurts

[–] [email protected] 2 points 7 months ago (1 children)

Kind of curious how you got that value. I think the ratio of circumference to diameter ("pi") is actually smaller in spherical geometry, in the most extreme case (the equator) it's just 1. You could say "pi = 5" for circles of a specific radius in hyperbolic geometry, I guess.

[–] [email protected] 2 points 7 months ago (1 children)

my mistake was using the sum of angles in a triangle which was kinda dum but whatever . I also tried calculating via the circumstance of a circle placed at a pole where π was 20x smaller for the case I was using but its not linear so I looked deeper which was a big mistake .

BTW the ratio of circumstance to radius for a circle which is also an equator of the space is ¼ not 1 (r=½π₀ , C=2π₀) .

[–] [email protected] 2 points 7 months ago (1 children)

BTW the ratio of circumstance to radius for a circle which is also an equator of the space is ¼ not 1 (r=½π₀ , C=2π₀) .

I think you mean 4, which makes the ratio of circumference to diameter 2 (either way, no idea how I messed up that one).

[–] [email protected] 2 points 7 months ago

oopsie :3